**Please help me to calculate following integrals. Show your**

16/02/2010Â Â· I don't know what you did at that web calculator, but when I plugged in (sin(3*x))^3 it gave me back (cos^3(3x) - 3 cos(3x)) / 9, which is the same as your second answer. The integration by substitution you did was correct.... 16/10/2010Â Â· âˆ« sin Â² (2x) dx = = (1/2) [ x - sin (4x) / 4 ] + C âˆ« sin Â² (2x) dx = = (x/2) - [ sin (4x) ] / 8 + C. Como Â· 8 years ago . 4. Thumbs up. 0. Thumbs down. Report Abuse. Comment. Add a comment. Submit Â· just now. Report Abuse. I think that this question violates the Community Guidelines. Chat or rant, adult content, spam, insulting other members,show more. I think that this question

**integrate cos^3x.sin^4x? Yahoo Answers**

29/01/2015Â Â· In this video, I demonstrate how to integrate sin^3(x)cos^4(x) by reserving a factor of sin(x) and converting the integrand into powers of cos(x). This then turns this integral into a simple power... 25/06/2012Â Â· Yahoo India Answers Sign in Mail âš™ Help. Account Info; Help; Send feedback

**calculus What's the the integral of $\tan(4x**

18/02/2012Â Â· int cos^3x * sin^4x dx = int cosx * cos^2x * sin^4x dx = int cosx [ 1- sin^2x] sin^4x dx = int cosx sin^4x dx - int cosx sin^6x dx [ let sinx= t so cosx dx= dt]... -e^x cos4x/4+1/4[e^x sin 4x/4 - 1/4Integral[e^x sin4x dx] at this point your instinct might be to think you are in an infinite loop of integrals, but look closely at the last integral on the right, it is a multiple of the original integral you had, so:

**Integral of (x^3*sin(x^4)) dx? Mathskey.com**

TRIGONOMETRIC INTEGRALS Integrals of the form Z cos(mx)cos(nx)dx, Z sin(nx)sin(mx)dxand Z cos(mx)sin(nx) In order to compute these integrals we recall the following identities... So let me rewrite this as, I'm in the home stretch really, this is going to be equal to 1/4 times the integral of 3/2 minus two cosine of two x. The derivative of four x is four, so it'd be great if I had a four out here. Let me rewrite 1/2 as four over eight. Really I'm just multiplying and dividing by four. That's one way to think about it. So I could say, plus 1/8 times four cosine of four

## How To Show Integral Sin 4x Dx 4 3

### Solved 4x5x + 2x-7dx 6x2+cos 2x-3dx Cos Mx Sin Nxdx 1

- integrate sin^4x.cosx? Yahoo Answers
- Calc II how to evaluate the integral of sin^3(2x)dx
- show that âˆ« sin^4 x dx = 3/8 x 1/4 sin 2x + 1/32 sin 4x
- How to integrate sin^3 x cos x dx? The Student Room

## How To Show Integral Sin 4x Dx 4 3

### The integral `int cos^5x*sin^4x dx` has to be determined. `int cos^5x*sin^4x dx` => `int cos x*cos^4x*sin^4 dx` => `int cos x*(1 - sin^2x)*(1 - sin^2x)*sin^4 dx`

- Let u = sin(x) which gives du/dx = cos(x) or cos(x) dx = du. Substitute into the integral to obtain Substitute into the integral to obtain cos(x) sin 4 (x) dx = u 4 du
- 21/02/2014Â Â· Upload failed. Please upload a file larger than 100 x 100 pixels; We are experiencing some problems, please try again. You can only upload files of type PNG, JPG or JPEG.
- Use integration by parts, but use the chain rule on sin^3 x no integration by parts would be unecessary as you can just make a substitution like the others suggested. 0
- I've been stuggling over this one for a while. Wolfram Alpha's worked solution isn't making sense to me. I suspect I may have to do the reverse...

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